R=10k Omega ,C_(1)=44.5 mu F,C_(2)=224 mu F,C_(3)=4.6 mu F The time constant of a RC circuit, tau =RC. Prove that tau has the units of time. The voltage across the capacitor, v_(c)=V(1-e^(-( iota )/( tau ))) where tau =RC=ln((V)/(V-v_(c)))=((1)/( tau ))t. Part 1: Single Capacitor (circuit 1) R=10k Omega ,C_(1)=44.5 mu F,V=4.784V Table 1 t

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R=10k Omega ,C_(1)=44.5 mu F,C_(2)=224 mu F,C_(3)=4.6 mu F The time constant of a RC circuit,  tau =RC. Prove that  tau  has the units of time. The voltage across the capacitor, v_(c)=V(1-e^(-( iota )/( tau ))) where  tau =RC=>ln((V)/(V-v_(c)))=((1)/( tau ))t. Part 1: Single Capacitor (circuit 1) R=10k Omega ,C_(1)=44.5 mu F,V=4.784V Table 1  tau  (experiment): ,s, tau  (calculated): Using the values of t and v_(c) in Table 1 , plot ln((V)/(V-v_(c)))vs.t to determine the time constant  tau  of the RC. Compare that value with the value obtained from  tau =RC_(1) expression.

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(Solved): R=10k\Omega ,C_(1)=44.5\mu F,C_(2)=224\mu F,C_(3)=4.6\mu F The time constant of a RC circuit, \tau ...

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