(Solved): S=n=0Mn!(Mn)!M!xn Where M and N are very large numbor (about 1020) and x is about O(1). ...
S=∑n=0Mn!(M−n)!M!xn Where M and N are very large numbor (about 1020) and x is about O(1). calculate lnS and the logarithm of the maximum term of the series.
we can use Stirling's appropriation for S. Stirling's approximation states that for large values of n, n! is approximately equal to . Using this approximation, we can rewrite the express for S as:
Taking the natural logarithm of both side we get: