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(Solved): S=n=0Mn!(Mn)!M!xn Where M and N are very large numbor (about 1020) and x is about O(1). ...




\[
S=\sum_{n=0}^{M} \frac{M ! x^{n}}{n !(M-n) !}
\]
Where \( M \) and \( N \) are very large numbor (about \( \left.10^{20}\r
Where and are very large numbor (about and is about . calculate and the logarithm of the maximum term of the series.


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we can use Stirling's appropriation for S. Stirling's approximation states that for large values of n, n! is approximately equal to
  . Using this approximation, we can rewrite the express for S as:

    

Taking the natural logarithm of both side we get:




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