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(Solved): solve for A and B \( \frac{5}{x-8}-\frac{-8}{x+5}+\frac{6 x+5}{x^{2}-3 x-40}=\frac{A}{B} \) ...


solve for A and B

\( \frac{5}{x-8}-\frac{-8}{x+5}+\frac{6 x+5}{x^{2}-3 x-40}=\frac{A}{B} \)
\( \frac{5}{x-8}-\frac{-8}{x+5}+\frac{6 x+5}{x^{2}-3 x-40}=\frac{A}{B} \)


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