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(Solved): Solve sin(4x) cos(2x) + cos(4x) sin(2x) = 1 exactly on the interval 0 < x < 2. NOTE: Enter t ...
Solve \( \sin (4 x) \cos (2 x)+\cos (4 x) \sin (2 x)=1 \) exactly on the interval \( 0 \leq x<2 \pi \) NOTE: Enter the exact, fully simplified answers. \[ x= \] \[ x= \] \[ x= \] \[ x= \] \[ x= \] \[ x= \]
Expert Answer
Formula: sin?(a+b)=sin?acos?b+cos?asin?b Then sin?(4x)cos?(2x)+cos?(4x)sin?(2x)=sin?(2x+4x) sin?(4x)cos?(2x)+cos?(4x)sin?(2x)=sin?(6x) Then the equati