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Solve the given initial value problem and determine at least approximately where the solution is v ...
Solve the given initial value problem and determine at least approximately where the solution is valid. (6x² + y ? 1) dx ? (6y ? x) dy = 0, y(1) = 0 x± ???24x³ + x² 12x 12 Y X 6 the solution is valid as long as x NOTE: Round your answer to three decimal places. 0.984