Solve the initial-value problem on (-1,00): (2x + 3)y" - (2x + 5)y' + 2y = (2x + 3)e2.0 y(0) = 0, y(0) = 0 Hint: Use the result of Exercise 3 and variation of parameters.

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Solve the initial-value problem on (-1,00): (2x + 3)y&#34; - (2x + 5)y' + 2y = (2x + 3)e2.0 y(0) = 0, y(0) = 0 Hint: Use the result of Exercise 3 and variation of parameters.

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