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(Solved): Summer high temperatures are distributed normally with a mean of 96.2 and a standard deviation of 4. ...



Summer high temperatures are distributed normally with a mean of 96.2 and a standard deviation of 4.9. NOTE: Round your z?z-score to 2 decimal places before calculating a probability.
Summer high temperatures are distributed normally with a mean of \( 96.2 \) and a standard deviation of 4.9. NOTE: Round your

Summer high temperatures are distributed normally with a mean of \( 96.2 \) and a standard deviation of 4.9. NOTE: Round your \( z \) - score to 2 decimal places before calculating a probability. What is the summer high temperature that is the 66 th percentile of this distribution? \( 94.2 \) 93 \( 99.4 \) \( 98.2 \) None of the above What is the probability that a randomly selected summer day has a high temperature of \( 98 ? \) \[ \begin{array}{l} 0.6443 \\ 0.3557 \\ 0.0853 \\ 0 \\ 0.9147 \end{array} \] What is the probability that a randomly selected summer day has a high temperature greater than 98 ? \[ \begin{array}{l} 0.3557 \\ 0 \\ 0.6443 \\ 0.9147 \\ 0.0853 \end{array} \] What is the probability that a randomly selected group of 14 summer days have an average high temperature greater than 98 ? \[ \begin{array}{l} 0.6443 \\ 0.9147 \\ 0.0853 \\ 0.3557 \end{array} \] 0


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solution : given that , mean ? = 96.2 standard deviation ? = 4.9 a) 66th percentile P(Z
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