(Solved): Suppose the skin temperature of a naked person is 35.1C when the person is standing inside a roo ...

Suppose the skin temperature of a naked person is $35.1^{\circ }\mathrm{C}$ when the person is standing inside a room whose temperature is $22.6^{\circ }\mathrm{C}$. The skin area of the individual is $1.48{\mathrm{m}}^2$. (a) Assuming the emissivity is 0.779 , find the net loss of radiant power from the body. (b) Determine the number of food Calories of energy ( 1 food Calorie $=4186\mathrm{J}$ ) that is lost in 11.5 hours due to the net loss rate obtained in part (a). Metabolic conversion of food into energy replaces this loss. Units (b) Number Units