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(Solved): The acceleration of a ball is given by \( a(x)=-5 k x^{2} \), where \( a \) is acceleration of the ...



The acceleration of a ball is given by \( a(x)=-5 k x^{2} \), where \( a \) is acceleration of the ball in \( m / s^{2}, k \)

The acceleration of a ball is given by \( a(x)=-5 k x^{2} \), where \( a \) is acceleration of the ball in \( m / s^{2}, k \) is a constant with unspecified units, and \( x \) is the position of the ball in \( m \). Consider the following initial conditions for position \( x_{0} \) and velocity \( v_{0} \) at \( t=0 s: x_{0}=8 \mathrm{~m} v_{0}=23 \mathrm{~m} / \mathrm{s} \) Use these conditions to detemine the velocity of the ball at \( x=13 \mathrm{~m} \). You may use \( k=0.03 \).


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Given Acceleration of the Ball a=?5kx2 a=dVdt=dVdx(dxdt)=Vdvdx=?5kx2 VdVdx=?5kx2 VdV=?5kx2dx In
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