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(Solved): The anhydrous form of Epsom salt is magnesium sulfate. From 16.0 g MgSO4 and 100 mL H2O at 25C. ...



The anhydrous form of Epsom salt is magnesium sulfate. From 16.0 g MgSO4 and 100
mL H2O at 25°C. What is the percent of mass

The anhydrous form of Epsom salt is magnesium sulfate. From 16.0 g MgSO4 and 100 mL H2O at 25°C. What is the percent of mass of MgSO4 in a prepared solution? (Density of water at 25°C is 0.997 g/mL). What is the molarity and molality of the prepared MgSO4 solution? (Assume that the density does not change with the addition of MgSO4 to water).


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Given, mass of solute MgSO4 = 16.0 g Volume of water, H2O = 100 mL Density of water = 0.997 g/mL So, mass of solvent, water = Density x Volume = (0.997 g/mL) x (100 mL) = 99.7 g = 0.0997
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