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(Solved): The area of a rectangle is 42yd^(2), and the length of the rectangle is 5yd more than twice the widt ...



The area of a rectangle is 42yd^(2), and the length of the rectangle is 5yd more than twice the width. Find the dimensions of the rectangle. Length : y Width : yd


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The area of a rectangle is      
Let the width is    yd
So according to the problem the length is    yd

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