(Solved): The base of a cerrain solid is the area bounded ahove by the graph of \( y=f(x)-16 \) and below by ...

The base of a cerrain solid is the area bounded ahove by the graph of \( y=f(x)-16 \) and below by the graph of \( y=9(x)=25 z^{3} \). Crisiaectioni perpendicular to the \( y \)-axis are squares, (See picture above, click for a better virw.) Wse the formula \[ V=\int_{0}^{b} A(y) d y \] to find the volume of the solid. The lower limit of integration is \( a= \) The upper limit of inegration is \( b= \) The side * of the square cross-secrion is the following function of \( y \) \[ A(v)= \] Thus the volume of the solid is \( V= \)