The binding energy for rubidium-87 nuclei is $7.312 \times 1013 J / mol$ . The binding energy per nucleon for rubidium-87 nuclei is MeV/nucleon. $1 MeV = 1.602 \times 1 0^{- 13} J N_{A} = 6.022 \times 1 0^{23}$ atoms $/ mol$

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The binding energy for rubidium-87 nuclei is 7.3121013J/mol. The binding energy per nucleon for rubidium-87 nuclei is MeV/nucleon. 1MeV=1.6021013JNA=6.0221023 atoms /mol

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