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(Solved): The boiling point of propane at 1atm(14.7psi) pressure is 42.0C and its H(vap) is 18.8 ...
The boiling point of propane at 1atm?(14.7psi) pressure is ?42.0?C and its ?H(vap) is 18.8kJ/mol. R=8.314×10?3kJ/mol?K. Calculate the pressure (in psi) of propane in a tank of liquid propane at 25.0?C.