The cost to advertise for a campaign is normally distributed with a weekly me of
$60,000
and a standard deviation of
$2000
. What is the probability the cos be more than
$63,000
next week? .8664 .4332 .0668 .5668

Question

The cost to advertise for a campaign is normally distributed with a weekly me of

$60,000

and a standard deviation of

$2000

. What is the probability the cos be more than

$63,000

next week? .8664 .4332 .0668 .5668

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