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(Solved): The eigenvectors of a square matrix A are all non-zero vectors v such that Av=\lambda v for some ...



The eigenvectors of a square matrix

A

are all

non-zero vectors

v

such that

Av=\lambda v

for some scalar

\lambda

, called the eigenvalue For example if

A=([5,1,-1],[4,2,-4],[3,-3,1])

then we can directly calculate that

([5,1,-1],[4,2,-4],[3,-3,1])([1],[0],[1])=

9.

([5,1,-1],[4,2,-4],[3,-3,1])([1],[0],[1])=

a So we have demonstrated that

([1],[0],[1])

is an eigenvector with eigenvalue Number Note: the Maple notation for the vector

([1],[2],[3])

is

{

(

:<1,2,3:)

} Similarly we can check that

([0],[1],[1])

is an eigenvector with eigenvalue

([1],[1],[0])

is an eigenvector with eigenvalue



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