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(Solved): The first error in this solved equation below is \[ \begin{aligned} \log (x+ ...



The first error in this solved equation below is
\[
\begin{aligned}
\log (x+5) &=2 \\
\log (x+5) &=\log 2 \\
x+5 &=2 \\
x &=7
???????If \( 3^{2 x-3}=27 \), then \( x \) is equal to
a) 4
b) 6
c) 2
d) 3 .

The first error in this solved equation below is \[ \begin{aligned} \log (x+5) &=2 \\ \log (x+5) &=\log 2 \\ x+5 &=2 \\ x &=7 \end{aligned} \] a) taking the log of 2 b) setting \( x+5=2 \) c) getting an answer of \( x=7 \) d) all of the above If \( 3^{2 x-3}=27 \), then \( x \) is equal to a) 4 b) 6 c) 2 d) 3 .


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