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(Solved): The height, h, in meters of a projectile after t seconds can be represented by h(t)=-4.9t^(2)+115t+1 ...



The height,

h

, in meters of a projectile after

t

seconds can be represented by

h(t)=-4.9t^(2)+115t+12.5

a. What is the object's average rate of change over the interval

0,10

?

(h(10)-h(\theta ))/(10)=(-4.9(10)^(2)+115(10)+12.5+(-4.9(\phi )^(2)+115(\phi )+12.5))/(10) =(660)/(10)=66

(b) What is the object's instantaneous velocity

a+t=10

? (c) What is the equation of the tangent line to

h(t)

at

t=10

(D) What is the object's accelerotion at

E=10

? (e) when is the object's instantaneous velocity equal to 0 ?



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