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(Solved): The Newton-Raphson formula to approximate a root of the function f(x) = 0 is (i) = X+1 X- (ii) - fo ...




The Newton-Raphson formula to approximate a root of the function
f(x) = 0 is
(i)
=
X+1 X-
(ii)
-
for i = 0, 1,..., n where x,
The Newton-Raphson formula to approximate a root of the function f(x) = 0 is (i) = X+1 X- (ii) - for i = 0, 1,..., n where x, is an initial guess. f(x?) f'(x?) Write a C++ program to generate an approximation for the root X+1 starting from the initial approximation xo. The iteration is stopped when the absolute difference Ix+1-xl is less than a given tolerance, &? = 10-5. Find the root of f(x) = 6x - ?1 + x² precise to 6 decimal places.


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The C++ function to find the root using Newton-Raphson formula, along with call to it to get root of the given function f(x), is below: #include
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