The normal distribution is given as N(x;a,b)=(1)/( sqrt(2 pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate the expectation value mu = int_(- infty )^( infty ) xN(x;a,b)dx and the variance sigma ^(2)= int_(- infty )^( infty ) (x- mu )^(2)N(x;a,b)dx

Question

The normal distribution is given as N(x;a,b)=(1)/( sqrt(2 pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate the expectation value  mu = int_(- infty )^( infty ) xN(x;a,b)dx and the variance  sigma ^(2)= int_(- infty )^( infty ) (x- mu )^(2)N(x;a,b)dx

Accepted Answer

Expert Answer to -  The normal distribution is given as N(x;a,b)=(1)/( sqrt(2 pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate

Answer

Solution for -  The normal distribution is given as N(x;a,b)=(1)/( sqrt(2 pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate

Answer

This an additional answer to -  The normal distribution is given as N(x;a,b)=(1)/( sqrt(2 pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate

(Solved): The normal distribution is given as N(x;a,b)=(1)/(\sqrt(2\pi b))e^(-((x-a)^(2))/(2b^(2))) Calculate ...

View Expert Answer

Expert Answer

Buy This Answer $5

Place Order

We Provide Services Across The Globe