(Solved): The picture here shows a Left Riemann Sum from x=1 to x=7 f(x)=8(x8)2+8 The picture here ...

The picture here shows a Left Riemann Sum from $x=1$ to $x=7$ $f(x)=?\frac{(x?8{)}^2}{8}+8$ The picture here shows a Left Riemann Sum from $x=1$ to $x=7$ for the function $f(x)=?\frac{(x?8{)}^2}{8}+8$ The width of the rectangles $=$ To find the height of the first rectangle, we would plug $x=$ into the $f$ $f(x)$ Area of Rectangle $1=$ Area of Rectangle $2=$ Area of Rectangle $3=$ Based on this Riemann Sum, the "area under the curve" from $x=1$ to $x=7$ is approximately