(Solved): The reaction of propane gas \( \left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\right) \) with ...

The reaction of propane gas \( \left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\right) \) with chlorine gas \( \left(\mathrm{Cl}_{2}\right) \) produces two monochloride products: \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}_{\text {and }} \) \( \mathrm{CH}_{3} \mathrm{CHClCH}_{3} \). The first is obtained in a \( 43 \% \) yield and the second in a \( 57 \% \) yield. How many grams of each product could theoretically be obtained from the reaction starting with \( 2.78 \) \( g \) of propane? \( =\quad \mathrm{g} \mathrm{C}_{3} \mathrm{H}_{7} \mathrm{Cl} \) (round to two decimal places) \( \mathrm{C}_{3} \mathrm{H}_{7} \mathrm{Cl} \)