(Solved): The simply supported, uniformly loaded beam carries a dead load of 1.2(k)/(f)t (including self-weigh ...
The simply supported, uniformly loaded beam carries a dead load of
1.2(k)/(f)t(including self-weight) and a live load of
2.75(k)/(f)t.
30%of the live load is of a sustained nature while the rest is intermittent. Calculate the following deflections. Remember for deflection calculations, we use service loads, not factored loads. (a) Calculate the instantaneous deflection due to dead load,
\Delta _(D,l), after the beam is first constructed. The
l_(eff )will be due to the moment caused only by the dead load. (b) Calculate the additional deflection caused after the live load is applied. Remember you need to calculate this as
\Delta _(D+L,I)-\Delta _(D,I)where
\Delta _(D,I)is from step (a). For
\Delta _(D+L,I), the
I_(eff )is due to the moment caused by D+L. (c) Calculate the long term deflection of the beam
\Delta _(D+S,LT)after 48 months. Please use the provided excel sheet to calculate the time-dependent sustained load factor. For this part, you can use the proportionality method since the beam is cracked under D+L (dead load + full live load).
