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(Solved): The steady-state temperature distribution in a one dimensional wall of thermal conductivity 50(W)/(m ...
The steady-state temperature distribution in a one dimensional wall of thermal conductivity
50(W)/(m^(2.))Kand thickness 50 mm is observed to be
T(C)=a+bx^(2), where
a=200C,b=
-4000(C)/(m^(2)), and
xis in meters. What is the heat generation rate in the wall Determine the heat fluxes at
x=LDetermine the heat fluxes at
x=0