The submarine U.S.S. Dallas shoots a torpedo at the Soviet submarine V.K. Konovalov, which is 6732 meters distant. The Konovalov cannot run away because it has had a reactor accident. After being ejected from the torpedo tube with an initial speed of 3.94 m/s, the torpedo accelerates with a constant acceleration of +0.196 m/s2 for 95.7 s, after which it continues on with uniform motion.
(a) What is the total time required for the torpedo to reach the Konovalov from the moment it was launched?
(b) After the torpedo reaches its final speed, by how much does the distance between it and the Konovalov decrease in ten seconds?
v = v0 + at Dx = v0t + ½ at2 v2 = v02 + 2aDx
when a = 0: Dx = vt, or D = RT