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(Solved): The value for the equilibrium constant for the following chemical reaction, the autoionization of wa ...
The value for the equilibrium constant for the following chemical reaction, the autoionization of water, is
1.0\times 10^(-14)at 298 K
2H_(2)O(I)larr->OH^(-)(aq)+H_(3)O^(+)(aq)K_(w)=1.0\times 10^(-14)Using this information and your equilibrium identities, select the correct value for the equilibrium expression for the reaction shown below (at 298 K as well) :
OH^(-)(aq)+H_(3)O^(+)(aq)larr->2H_(2)O(l)K= ? 