The wad of clay A is projected as shown at the same instant that cylinder B is released. The two bodies collide and stick together at C
and then ultimately strike the horizontal surface at D. Determine the horizontal distance d. Use the values v_(0)=14(m)/(s),\theta =32\deg ,L=9.0
m,m_(A)=0.5kg, and m_(B)=0.1kg.
Part 1
Part 2
Your answer is partially correct.
Find the velocity of each body just before the collision.
Answers:
v_(A)=(,i+i j)( m)/(s)
v_(B)=(,i+ j)( m)/(s)