This algorithm will multiple a number by repeatedly adding the value of A the number of times stated in the value of B.
For example, if A = 10 and B = 3, This algorithm will perform the following :
10 + 10 + 10 = 30
Tip: Notice that this only added the value of A 3 times but in your response, you will see it shows up to 4 iterations.
If this happens in any of these exercises, the proper answer would be "Loop Ended" for both Count and Product.
A = 8 B = 2
Get A
Get B
STEP 1 If A or B = 0
Then Set Product to = 0 and Go To STEP 3
Else Set Count to 0 and Set Product to 0 and Go To STEP 2
STEP 2 While Count < B
Set Product to (Product + A)
Set Count to (Count + 1)
End of Loop;
STEP 3 Print the value of Product
STEP 4 Stop
I am providing the solution in C, i hpe you will