(Solved): this answer this it incorrect. Complete parts (a) through (f).
(c) Calculate d and sd. d=0.029 ...
this answer this it incorrect.
Complete parts (a) through (f).
(c) Calculate d and sd. d=0.029 (Round to three decimal places as needed.) Calculate sd. sd=0.0312 (Round to four decimal places as needed.) (d) Find the standardized test statistic t. (Round to two decimal places as needed.) (e) Decide whether to reject or fail to reject the null hypothesis. The P-value is 0.004 . (Round to three decimal places as needed.)
Solution:-Given data is as below:-
Now consider from the above table,sample size, n = 12sample mean for the differences, d- = = = -0.03008 = -0.030standard deviation for difference scores, sd = = = 0.029889 = 0.0299(c) = -0.030sd = 0.0299
Read the given data and note the information.Substitute values of data in the formulas of mean and standard deviation to execute them.