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(Solved): This shows that
y 1y1(t)equals=e Superscript negative 11 te11t
and
y 2y2(t)equals=t e ...
This shows that
y 1y1(t)equals=e Superscript negative 11 te−11t
and
y 2y2(t)equals=t e Superscript negative 11 tte−11t
are solutions to the equation from the first step. Now find the limit of each as
tright arrow→infinity∞.