(Solved): Trial 1 .00125 A. Determination of the Amount of Calcium in the Saturated Solution by EDTA Titratio ...

Trial 1 .00125 A. Determination of the Amount of Calcium in the Saturated Solution by EDTA Titration EDTA 0100LM Trial 2 Trial 3 Initial volume .43 mL 9.68 mL 18.71 mL 9.68 m2 18.71 mL Final volume 27.67mL 9.03 mL 8.96ml Volume used [Ca?) 9.26x103 9.04x10-3 9.00x 10 Below, show calculation of [Ca] and [IO] for one of the trials: 9.03 mL :.00903 LEDTAX 01001M EDTA = 9.63903x10 9,0390346é Caxtmol- 9.04 x 10-3 -2 . OIL [IO] 1.85010 1.81x102 Kip 3.18x10-6 Fill in concentrations for one of the solutions using an ICE table below: Ca(10)2 (8) Ca (ag) 2 10, (ag) 1000 -5 (2) (9.04x103) 2 = 1.87810* 7.80x102 2.92x106 2.96x10-6 + 1 ? C + 2x +X X=9.04x103 2x= 1.81x102 E 3.02x10-6 1.40x10? Average K. Standard deviation What is the solubility of calcium iodate in water in grams per liter? Show your calculation below.