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(Solved): Two stones are separated by a vertical distance y (in meters) from each other. One stone i ...



Two stones are separated by a vertical distance y (in meters) from each other. One stone is thrown down with an initial velocity v01 = -47 m/s and the other is thrown up from the ground with an initial v02 = 29 m/s at the same time the other is thrown.

How far, in meters, must the stones be separated so they hit the ground at the same time?



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1. For the stone 2 which is thrown upward, we've - Initial velocity, u=29 ms Acceleration, a=?g Displacement, S=0 Using 2nd equation of motion, we get
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