(Solved): Use python to solve the problem line1 needs to be like this: def hexadecimal_to_decimal_converter(he ...

Use python to solve the problem

line1 needs to be like this:

def hexadecimal_to_decimal_converter(hexadecimal_string):

The hexadecimal number system is a base 16 number system. There are 16 digits in this number system - \( 0,1,2,3,4,5,6,7,8,9, A, B, C, D, E \), and F where \( A=10, B=11, C=12, D=13, E=14 \), and \( F=15 \). Let's say you are given a hexadecimal number \( d_{n-1} d_{n-2} \cdots d_{1} d_{0} \) then the corresponding decimal number can be calculated as follows: \[ d_{n-1} \cdot 16^{n-1}+d_{n-2} \cdot 16^{n-2}+\cdots+d_{1} \cdot 16^{1}+d_{0} \cdot 16^{0} \] For example, 2A in hexadecimal is 42 in decimal as shown below. \[ 2 A=2 \cdot 16^{1}+10 \cdot 16^{0}=42 \] Define the function hexadecimal_to_decimal_converter () that takes a single string parameter - hexadecimal_string. You can assume that hexadecimal_string will always be a valid string representation of a hexadecimal integer. The function should calculate and return the decimal integer equivalent of this hexadecimal integer. Some examples of the function being called are shown below. For example: Test hexadecimal_string \( = \) "7" decimal_value = hexadecimal_to_decimal_converter(hexadecimal_strir print(f"\{hexadecimal_string\} in hexadecimal is \{decimal_value\} in hexadecimal_string = "D" decimal_value = hexadecimal_to_decimal_converter(hexadecimal_strir print(f"\{hexadecimal_string\} in hexadecimal is \{decimal_value\} in hexadecimal_string = "FF" decimal_value = hexadecimal_to_decimal_converter(hexadecimal_strir print(f" \( f \) "hexadecimal_string \( \} \) in hexadecimal is \{decimal_value \( \} \) in For example: