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(Solved): Use the substitution t=8tan to find the integral. NOTE: Do not include the +C in your answer. ...



Use the substitution \( t=8 \tan \theta \) to find the integral. NOTE: Do not include the \( +C \) in your answer.
Use the substitution to find the integral. NOTE: Do not include the in your answer.


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Given integral is ?1(64+t2)32dtLet t=8tan??dtd(?)=8sec2?dt=8sec2?d(?)?1(64+t2)32dt=?1((64+64tan2
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