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(Solved): = Using the Alternating Series Test on the series (-1)" In n we see that bn n n=1 (1) bn is ...



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Using the Alternating Series Test on the series ?(-1) In n we see that bn
n
n=1
(1) bn is choose
for all n ? 3
(2) bn is

? = Using the Alternating Series Test on the series ?(-1)" In n we see that bn n n=1 (1) bn is choose for all n ? 3 (2) bn is choose on n ? 3 (3) lim bn = choose n ? ? Hence, the series is choose In n n and


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