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(Solved): Very easy. Can some one please explain this to me? Thanks A particle's position in meters is given b ...



Very easy. Can some one please explain this to me? Thanks

A particles position in meters is given by the furiction \( x(t)=2.0 t^{4}-3.0 t \). What is the velocity of the particle at
A particle's position in meters is given by the furiction \( x(t)=2.0 t^{4}-3.0 t \). What is the velocity of the particle at \( t=3.0 \mathrm{~s} \) ? \( 130 \mathrm{~m} / \mathrm{s} \) \( 150 \mathrm{~m} / \mathrm{s} \) \( 213 \mathrm{~m} / \mathrm{s} \) \( 260 \mathrm{~m} / \mathrm{s} \) \( 310 \mathrm{~m} / \mathrm{s} \)


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here given : x(t) = 2.
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