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(Solved): What is the \( \mathrm{OH}^{-} \)concentration? [Hint: Use the \( K_{\text {w }} \) relationship.] ...




What is the \( \mathrm{OH}^{-} \)concentration? [Hint: Use the \( K_{\text {w }} \) relationship.]
Express your answer with t
Suppose \( 1.34 \mathrm{~mol} \) of \( \mathrm{HCl} \) is dissolved in enough water to give \( 625.0 \mathrm{~mL} \) of solut
What is the \( \mathrm{H}_{3} \mathrm{O}^{+} \)concentration? [Hint: When 1 mole of \( \mathrm{HCl} \) dissociates, we get 1
What is the \( \mathrm{OH}^{-} \)concentration? [Hint: Use the \( K_{\text {w }} \) relationship.] Express your answer with the appropriate units. Suppose \( 1.34 \mathrm{~mol} \) of \( \mathrm{HCl} \) is dissolved in enough water to give \( 625.0 \mathrm{~mL} \) of solution. What is the \( \mathrm{H}_{3} \mathrm{O}^{+} \)concentration? [Hint: When 1 mole of \( \mathrm{HCl} \) dissociates, we get 1 mole of \( \mathrm{H}_{3} \mathrm{O}^{+} \)ions because the acid is strong and monoprotic. Your answer should be in moles of \( \mathrm{H}_{3} \mathrm{O}^{+} \)per liter of solution.] Express your answer with the appropriate units.


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A). Moles of HCl = 1.34 mol Volume of Solution = 625.0 mL When HCl dissolved in water HCl + H2O ---
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