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(Solved): What is the rG for the following reaction (in kJ mol-1) at 298 K? 2 Si (s) + 3 H2 (g) Si2H6 ( ...



What is the ?rG for the following reaction (in kJ mol-1) at 298 K?

2 Si (s) + 3 H2 (g) ? Si2H6 (g)

The conditions for this reaction are: PH2 = 0.14 bar PSi2H6 = 0.89 bar

Please use the method of Gibbs energy of formation to calculate ?rG° if needed.

For partial credit, enter the value of "Q" for this reaction.



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Explanation:To calculate ?rG for the given reaction at 298 K, we need to use the equation:?rG = ?rG° + RT ln(Q)where ?rG° is the standard Gibbs energy
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