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Write down the slope of the straight line-of-best-fit from your graph (Make sure to use the correct units.) Slope

`=`

`q,`

`q,`

`n=-1,756\times 10^(3) (Kelun ) `

Using the value you obtained for the slope, calculate the molar heat of vaporization,

`\Delta H_(vap )`

, in kJ .

`\Delta H_(vap )=`

`q,`

Neatly show your work.

```
\Delta H_(rap )=-(-1.1756\times 10^(3)(K))\times 2,303\times 8.31(J)/(m)od.k
=33606,21(J)/(m)ol
```