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[Solved]: y^(')=-(2y)/(x) Cpx^(p-1)=-2Cx^(p) pCx^(p-1)=-
Home / Expert Answers / Algebra / y-39-2y-x-cpx-p-1-2cx-p-pcx-p-1-2cx-p-1-pcx-p-1-2cx-p-could-you-explain-how-the-pa527

(Solved): y^(')=-(2y)/(x) Cpx^(p-1)=-2Cx^(p) pCx^(p-1)=-2Cx^(p-1) pCx^(p-1)=-2Cx^(p)Could you explain how the ...



y^(')=-(2y)/(x) Cpx^(p-1)=-2Cx^(p) pCx^(p-1)=-2Cx^(p-1) pCx^(p-1)=-2Cx^(p)

Could you explain how the x vanishes in the denominator and why does the left hand side have predict at the start but the right does not?



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